08-28-2013, 02:25 PM
(This post was last modified: 04-20-2014, 04:37 PM by HomeMadeAudioProject.)
<blockquote class="ipsBlockquote" data-author="HomeMadeAudioProject" data-cid="8289" data-time="1376844902">
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<p>
.snaga 6k8 otpornika treba biti P=(Unap-15V)^2 / 6800 pa puta dva i najvise zavisi od ispravljenog napona grane napajanja pojacala.
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</blockquote>
<p>Po toj računici bi u mom slučaju bilo bilo: P=((((35Vac x 1,41)-15)<span style="background-color:rgb(247,247,247);font-size:12px;">^2</span>)/6800)x2</p>
<p></p>
<p>P=(((49,5-15)<span style="background-color:rgb(247,247,247);font-size:12px;">^2</span>)/6800)x2</p>
<p></p>
<p>P=(1190,25/6800)x2</p>
<p></p>
<p>P=0,17503676470588235294117647058824 x 2</p>
<p></p>
<p><span style="color:#00ff00;"><strong>P=0,35</strong></span>007352941176470588235294117647</p>
<p></p>
<p><strong>P=0,35W?</strong></p>
<p></p>
<p>Da li mi je dobar račun?? :Thinking:</p>
<div>
<p>
.snaga 6k8 otpornika treba biti P=(Unap-15V)^2 / 6800 pa puta dva i najvise zavisi od ispravljenog napona grane napajanja pojacala.
</p>
</div>
</blockquote>
<p>Po toj računici bi u mom slučaju bilo bilo: P=((((35Vac x 1,41)-15)<span style="background-color:rgb(247,247,247);font-size:12px;">^2</span>)/6800)x2</p>
<p></p>
<p>P=(((49,5-15)<span style="background-color:rgb(247,247,247);font-size:12px;">^2</span>)/6800)x2</p>
<p></p>
<p>P=(1190,25/6800)x2</p>
<p></p>
<p>P=0,17503676470588235294117647058824 x 2</p>
<p></p>
<p><span style="color:#00ff00;"><strong>P=0,35</strong></span>007352941176470588235294117647</p>
<p></p>
<p><strong>P=0,35W?</strong></p>
<p></p>
<p>Da li mi je dobar račun?? :Thinking:</p>
The only way out...
...is the way through!
...is the way through!